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Maths for SG Primary Schools

Primary 5 maths · Measurement & time · About 12 minutes

Find areas of composite rectangles, squares and triangles

Find the right-angle relationship before using a dimension. For a composite surface, keep the pieces separate.

Start the interactive lesson →Open practice activity

What you will learn

Models used: number sentences, stories, diagrams.

Before you start

A rectangle with a triangular roof

Split the house shape at the dotted line. We have a rectangle and a triangle.

  1. The dashed line separates the rectangular wall from the triangular roof; it is inside the house.

    Split the house shape at the dotted line. We have a rectangle and a triangle.

    Base and perpendicular height define the matching rectangle or parallelogram. The triangle’s area is half their product.

    base 6 cm4 cm2 cm
  2. The dashed line separates the rectangular wall from the triangular roof; it is inside the house.

    The rectangle covers 6 × 4 = 24 square centimetres. The roof covers half of 6 × 2, which is 6.

    base 6 cm4 cm2 cm
  3. The dashed line separates the rectangular wall from the triangular roof; it is inside the house.

    The two parts meet along an edge, without overlapping. Add their areas.

    24 + 6 = 30 cm²

    base 6 cm4 cm2 cm
What did the picture help us see?

The two parts meet along an edge, without overlapping. Add their areas.

Worked example: A new example, together

A house-shaped figure has a 6 cm by 3 cm rectangle and a triangular roof with base 6 cm and height 1 cm. Find its area.

base 6 cmheight 3 cm1 cm roof height
Use the perpendicular height, not a sloping edge.
  1. Find the right-angle relationship before using a dimension. For a composite surface, keep the pieces separate.

    Two matching triangles make a rectangle or parallelogram with the same base and height.

    base 6 cmheight 3 cm1 cm roof height
    Use the perpendicular height, not a sloping edge.
  2. Triangle area = half of base × perpendicular height.

    base 6 cmheight 3 cm1 cm roof height
    Use the perpendicular height, not a sloping edge.
    A house-shaped figure has a 6 cm by 3 cm rectangle and a triangular roof with base 6 cm and height 1 cm. Find its area.

    21 cm²

  3. Triangle area = half of base × perpendicular height.

    base 6 cmheight 3 cm1 cm roof height
    Use the perpendicular height, not a sloping edge.
  4. Rectangle: 6 × 3 = 18 cm²; triangle: 6 × 1 ÷ 2 = 3 cm².

    base 6 cmheight 3 cm1 cm roof height
    Use the perpendicular height, not a sloping edge.
  5. Add the non-overlapping areas: 21 cm².

    base 6 cmheight 3 cm1 cm roof height
    Use the perpendicular height, not a sloping edge.
  6. Check the result against the question we started with.

    The two parts meet along an edge and do not overlap.

    We found 21 cm². Two matching triangles make a rectangle or parallelogram with the same base and height.

    base 6 cmheight 3 cm1 cm roof height
    Use the perpendicular height, not a sloping edge.

Common mistakes to discuss

Check your understanding

Explain your reasoning to an adult, then try a fresh question in the interactive lesson. A result from one attempt is not proof of lasting mastery.

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